public final class Double

The largest positive finite value of type double. It is equal to the value returned by Double.longBitsToDouble(0x7fefffffffffffffL) See Also:Constant Field Values

The smallest positive value of type double. It is equal to the value returned by Double.longBitsToDouble(0x1L).

A Not-a-Number (NaN) value of type double. It is equal to the value returned by Double.longBitsToDouble(0x7ff8000000000000L). See Also:Constant Field Values

The negative infinity of type double. It is equal to the value returned by Double.longBitsToDouble(0xfff0000000000000L). See Also:Constant Field Values

The positive infinity of type double. It is equal to the value returned by Double.longBitsToDouble(0x7ff0000000000000L). See Also:Constant Field Values

Constructs a newly allocated Double object that represents the primitive double argument. value - the value to be represented by the Double.

Returns the value of this Double as a byte (by casting to a byte).

Returns a representation of the specified floating-point value according to the IEEE 754 floating-point “double format” bit layout. Bit 63 (the bit that is selected by the mask 0x8000000000000000L) represents the sign of the floating-point number. Bits 62-52 (the bits that are selected by the mask 0x7ff0000000000000L) represent the exponent. Bits 51-0 (the bits that are selected by the mask 0x000fffffffffffffL) represent the significand (sometimes called the mantissa) of the floating-point number. If the argument is positive infinity, the result is 0x7ff0000000000000L. If the argument is negative infinity, the result is 0xfff0000000000000L. If the argument is NaN, the result is 0x7ff8000000000000L. In all cases, the result is a long integer that, when given to the longBitsToDouble(long) method, will produce a floating-point value equal to the argument to doubleToLongBits.

Returns the double value of this Double.

Compares this object against the specified object. The result is true if and only if the argument is not null and is a Double object that represents a double that has the identical bit pattern to the bit pattern of the double represented by this object. For this purpose, two double values are considered to be the same if and only if the method returns the same long value when applied to each. Note that in most cases, for two instances of class Double, d1 and d2, the value of d1.equals(d2) is true if and only if d1.doubleValue() == d2.doubleValue() also has the value true. However, there are two exceptions: If d1 and d2 both represent Double.NaN, then the equals method returns true, even though Double.NaN==Double.NaN has the value false. If d1 represents +0.0 while d2 represents -0.0, or vice versa, the equals test has the value false, even though +0.0==-0.0 has the value true. This allows hashtables to operate properly.

Returns the float value of this Double.

Returns a hashcode for this Double object. The result is the exclusive OR of the two halves of the long integer bit representation, exactly as produced by the method , of the primitive double value represented by this Double object. That is, the hashcode is the value of the expression: (int)(v^(v»>32)) where v is defined by: long v = Double.doubleToLongBits(this.doubleValue());

Returns the integer value of this Double (by casting to an int).

Returns true if this Double value is infinitely large in magnitude.

Returns true if the specified number is infinitely large in magnitude.

Returns true if this Double value is the special Not-a-Number (NaN) value.

Returns true if the specified number is the special Not-a-Number (NaN) value.

Returns the double-float corresponding to a given bit representation. The argument is considered to be a representation of a floating-point value according to the IEEE 754 floating-point “double precision” bit layout. That floating-point value is returned as the result. If the argument is 0x7ff0000000000000L, the result is positive infinity. If the argument is 0xfff0000000000000L, the result is negative infinity. If the argument is any value in the range 0x7ff0000000000001L through 0x7fffffffffffffffL or in the range 0xfff0000000000001L through 0xffffffffffffffffL, the result is NaN. All IEEE 754 NaN values of type double are, in effect, lumped together by the Java programming language into a single value called NaN. In all other cases, let s, e, and m be three values that can be computed from the argument: int s = ((bits » 63) == 0) ? 1 : -1; int e = (int)((bits » 52) & 0x7ffL); long m = (e == 0) ? (bits & 0xfffffffffffffL) « 1 : (bits & 0xfffffffffffffL) | 0x10000000000000L; Then the floating-point result equals the value of the mathematical expression 2e-1075.

Returns the long value of this Double (by casting to a long).

Returns a new double initialized to the value represented by the specified String, as performed by the valueOf method of class Double.

Returns the value of this Double as a short (by casting to a short).

Returns a String representation of this Double object. The primitive double value represented by this object is converted to a string exactly as if by the method toString of one argument.

Returns a new Double object initialized to the value represented by the specified string. The string s is interpreted as the representation of a floating-point value and a Double object representing that value is created and returned. If s is null, then a NullPointerException is thrown. Leading and trailing whitespace characters in s are ignored. The rest of s should constitute a FloatValue as described by the lexical rule: where and are as defined in Section 3.10.2 of the . If it does not have the form of a , then a NumberFormatException is thrown. Otherwise, it is regarded as representing an exact decimal value in the usual “computerized scientific notation”; this exact decimal value is then conceptually converted to an “infinitely precise” binary value that is then rounded to type double by the usual round-to-nearest rule of IEEE 754 floating-point arithmetic. Finally, a new object of class Double is created to represent the double value.

Returns the object instance of i

Compares this object to the specified object to determine their relative order.